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(F)=-2F^2+16F-30
We move all terms to the left:
(F)-(-2F^2+16F-30)=0
We get rid of parentheses
2F^2-16F+F+30=0
We add all the numbers together, and all the variables
2F^2-15F+30=0
a = 2; b = -15; c = +30;
Δ = b2-4ac
Δ = -152-4·2·30
Δ = -15
Delta is less than zero, so there is no solution for the equation
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